Вычислите.........................................
1. a=(∛a)³, 8=2³ (a+8)/(a²/³-2∛a+4)[(∛a+2)*(a²/³-2∛a+2²)] / [a²/³-2∛a+4]=∛a+2 2. log₁/₄48-log₁/₄12=log₁/₄(48:12)=log₁/₄4=-1