0\\\\Po -teoreme-Vieta-x_1=-1,x_2=6\\ + + + + + (-1) - - - - - - (6) + + + + \\x\in (-\infty,-1)U(6,+\infty)" alt=" \left \{ {{x^2-5x+6 \geq 0} \atop {x^2-5x+6\ne 0}} \right. \to x^2-5x+6>0\\\\Po -teoreme-Vieta-x_1=-1,x_2=6\\ + + + + + (-1) - - - - - - (6) + + + + \\x\in (-\infty,-1)U(6,+\infty)" align="absmiddle" class="latex-formula">