(2b+11c)-(5b+2c) при b=-0,1, c=-0,7

Question

(2b+11c)-(5b+2c) при b=-0,1, c=-0,7

Answer 1

(2b+11c)-(5b+2c)=2b+11c-5b-2c=-3b+9c
-3(-0,1)+9(-0,7)=0,3-6,3=-6

Answer 2

Ответ:
(2b+11c)-(5b+2c)=
=2b+11c-5b-2c=
=-3b+9c=
=-3*(-0,1)+9*(-0,7)=
=0,3-6,3=-6